• Guess the Output: PRINTF("%d");




    1. When we write printf("%d",x); this means compiler will print the
    value of x. But as here, there is nothing after %d so compiler will show
    in output window garbage value.


    2. When we use %d the compiler internally uses it to access the
    argument in the stack (argument stack). Ideally compiler determines
    the offset of the data variable depending on the format specification
    string. Now when we write printf("%d",a) then compiler first accesses
    the top most element in the argument stack of the printf which is %d
    and depending on the format string it calculated to offset to the actual
    data variable in the memory which is to be printed. Now when only %d
    will be present in the printf then compiler will calculate the correct
    offset (which will be the offset to access the integer variable) but as
    the actual data object is to be printed is not present at that memory
    location so it will print what ever will be the contents of that memory
    location.

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